Receiver Tank Principle and Calculations
by Lee Evans
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A receiver tank is
a form of dry compressed air storage in a compressed air system. Normally
installed after drying and
filtration, and before end use devices, receiver tanks help to store compressed
air. The compressed air is created by the supply side, stored by the
receiver tank, and released as needed to the demand side of the system.
But how does this work?
The principle behind this concept is rooted in pressure
differentials. Just as we increase pressure when reducing volume of a
gas, we can increase volume when reducing pressure. So, if we have a
given volume of compressed air at a certain pressure (P1), we will have a
different volume of compressed air when converting this same air to a different
pressure (P2).
This is the idea behind a receiver tank. We store the
compressed air at a higher pressure than what is needed by the system, creating
a favorable pressure differential to release compressed air when it is
needed. And, in order to properly use a receiver tank, we must be able to
properly calculate the required size/volume of the tank. To do so, we
must familiarize ourselves with the receiver tank capacity formula.
Receiver tank capacity formula
V = ( T(C-Cap)(Pa)/(P1-P2) )
Where,
V = Volume of receiver tank in cubic feet
T = Time interval in minutes during which compressed air demand
will occur
C = Air requirement of demand in cubic feet per minute
Cap = Compressor capacity in cubic feet per
minute
Pa = Absolute atmospheric pressure, given
in PSIA
P1 = Initial tank pressure (Compressor
discharge pressure)
P2 = minimum tank pressure (Pressure
required at output of tank to operate compressed air devices)
An example:
Let’s consider an application with an intermittent demand spike
of 50 SCFM of compressed air at 80 PSIG. The system is operating from a
10HP compressor which produces 40 SCFM at 110 PSIG, and the compressed air
devices need to operate for (5) minutes at this volume.
We can use a receiver tank and the pressure differential between
the output of the compressor and the demand of the system to create a reservoir
of compressed air. This stored air will release into the system to
maintain pressure while demand is high and rebuild when the excess demand is
gone.
In this application, the values are as follows:
V = ?
T = 5 minutes
C = 50 CFM
Cap = 40 SCFM
Pa = 14.5 PSI
P1 = 110 PSIG
P2 = 80 PSIG
Running these numbers out we end up with:
This means we will need a 24.2 gallon (91,6 liters) receiver tank to store the
required volume of compressed air needed in this system. Doing so will
result in a constant supply of 80 PSIG, even at a demand volume which exceeds the
supply capability of the compressor. By installing a properly sized
receiver tank with proper pressure differential, the reliability of the system
is improved.
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